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author | David A. Madore <david+git@madore.org> | 2016-05-26 18:24:25 +0200 |
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committer | David A. Madore <david+git@madore.org> | 2016-05-26 18:24:25 +0200 |
commit | 37a912ae129a042a184f9e0a811a123122df51a5 (patch) | |
tree | d8cc2f4e155d825becda937eef4a2699bfc0913b | |
parent | 09af2d3256d2e2873b4533ef4e843a9674483b2d (diff) | |
download | mitro206-37a912ae129a042a184f9e0a811a123122df51a5.tar.gz mitro206-37a912ae129a042a184f9e0a811a123122df51a5.tar.bz2 mitro206-37a912ae129a042a184f9e0a811a123122df51a5.zip |
Fix error in labeling of questions.
-rw-r--r-- | controle-20160421.tex | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/controle-20160421.tex b/controle-20160421.tex index 8720f49..4360c6b 100644 --- a/controle-20160421.tex +++ b/controle-20160421.tex @@ -642,9 +642,9 @@ de l'exercice \ref{game-for-nim-product}. \smallbreak -(3) (b) Montrer que si $\alpha'\neq\alpha$ et $\beta'\neq\beta$, alors +(3) (a) Montrer que si $\alpha'\neq\alpha$ et $\beta'\neq\beta$, alors $(\alpha'\otimes\beta) \oplus (\alpha\otimes\beta') \oplus -(\alpha'\otimes\beta') \neq \alpha\otimes\beta$.\spaceout (a) En +(\alpha'\otimes\beta') \neq \alpha\otimes\beta$.\spaceout (b) En déduire que si $\alpha\otimes\beta = \alpha\otimes\beta'$ alors $\alpha=0$ ou bien $\beta=\beta'$. |