1 files changed, 13 insertions, 2 deletions
diff --git a/transp-inf110-01-calc.tex b/transp-inf110-01-calc.tex
index 9034397..769e1e4 100644
--- a/transp-inf110-01-calc.tex
+++ b/transp-inf110-01-calc.tex
@@ -1,7 +1,7 @@
 %% This is a LaTeX document.  Hey, Emacs, -*- latex -*- , get it?
 \documentclass[mathserif,a4paper,aspectratio=169]{beamer}
 %\documentclass[a4paper]{article}
-%\usepackage[envcountsect,noxcolor]{beamerarticle}
+%\usepackage{beamerarticle}
 \usepackage[shorthands=off,french]{babel}
 \usepackage[utf8]{inputenc}
 \usepackage[T1]{fontenc}
@@ -25,12 +25,21 @@
 \usepackage{graphicx}
 \usepackage{tikz}
 \usetikzlibrary{arrows,automata,calc}
+\usepackage{hyperref}
 %
 \newcommand{\itempoint}{\strut\hbox{\color{beamerstructure}\donotcoloroutermaths$\blacktriangleright$}\nobreak\hskip.5em plus.5em\relax}
 \renewcommand{\thefootnote}{\textdagger}
 \newcommand{\dbllangle}{\mathopen{\langle\!\langle}}
 \newcommand{\dblrangle}{\mathclose{\rangle\!\rangle}}
 %
+\mode<article>{
+    \newcommand{\donotcoloroutermaths}{\relax}
+    \renewcommand{\frametitle}[1]{\subsubsection*{#1 {\footnotesize[transp. \insertframenumber]}}}
+    \newcommand{\myitemmark}{\hbox{$\blacktriangleright$}}
+    \renewcommand{\itempoint}{\strut\myitemmark\nobreak\hskip.5em plus.5em\relax}
+    \setlength{\parindent}{0pt}
+}
+%
 %
 %
 \title{Calculabilité}
@@ -45,7 +54,7 @@
 }
 \setbeamercolor{myhighlight}{fg=black,bg=white!90!green}
 \begin{document}
-\mode<article>{\maketitle}
+\mode<article>{\maketitle\renewcommand{\labelitemi}{\myitemmark}}
 %
 \setlength\abovedisplayskip{2pt plus 2pt minus 2pt}
 \setlength\belowdisplayskip{2pt plus 2pt minus 2pt}
@@ -2749,9 +2758,11 @@ prenant en entrée $m \in \mathbb{N}$ :
 \smallskip
 
 Soit $b(e,x)$ le code de l'algorithme qu'on vient de décrire :
+
 \centerline{$\varphi^{(1)}_{b(e,x)} = f$ si $\varphi^{(1)}_e(x)\downarrow$
 \quad et\quad
 $\varphi^{(1)}_{b(e,x)} = {\uparrow}$ si $\varphi^{(1)}_e(x)\uparrow$}
+
 notamment $\varphi^{(1)}_{b(e,x)} \in F$ ssi $\varphi^{(1)}_e(x)\downarrow$
 \textcolor{brown}{($\leftarrow$ c'est là la réduction)}.\hfill  …/…