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authordavid <david>2009-01-12 18:52:53 +0000
committerdavid <david>2009-01-12 18:52:53 +0000
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Make this a little more detailed.
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@@ -92,7 +92,7 @@ Les deux questions suivantes sont indépendantes.
(note : $128 = 2^7$) ?
\begin{corrige}
-(1) Comme $11$ et $31$ sont premiers entre eux,
+(1) Comme $11$ et $31$ sont premiers entre eux, le théorème chinois affirme
$\mathbb{Z}/341\mathbb{Z} \cong (\mathbb{Z}/11\mathbb{Z}) \times
(\mathbb{Z}/31\mathbb{Z})$, donc il suffit de prouver $a^{31} \equiv
a \pmod{31}$ et $a^{31} \equiv a \pmod{11}$ pour tout $a